Fabrik8
Overcomplicator
- Joined
- May 27, 2015
- Location
- Huntersville
And here's the rest for the cable solution with the cable at 90 degrees to the pole; summing moments about point A.
I'm just using the component of the weights that are perpendicular to the pole, because moments are a perpendicular force applied at a distance (basically a torque).
Notice how the two weights of the pole (W1 for triangle and W2 for rectangle) are just two parts of the moment summation, super easy. No need to combine them, like I said before.
If the cable was at some other angle to the pole, there would just be an added "sin(whatever angle)" after the cable tension, similar to the weights.
Understanding the problem is the hard part, after that the math is usually pretty straightforward.
I'm just using the component of the weights that are perpendicular to the pole, because moments are a perpendicular force applied at a distance (basically a torque).
Notice how the two weights of the pole (W1 for triangle and W2 for rectangle) are just two parts of the moment summation, super easy. No need to combine them, like I said before.
If the cable was at some other angle to the pole, there would just be an added "sin(whatever angle)" after the cable tension, similar to the weights.
Understanding the problem is the hard part, after that the math is usually pretty straightforward.
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