No
Lets use your numbers
2 cases each having
2.28 HIGH ranges
4.7 Low range
With only 1 case your ratios are
2.28
4.7
With 2 cases
Case 1 2wd + Case 2 HIGH = 2.28
CASE 1 2wd + CASE 2 LOW = 4.7
CASE 1 High (2.28) + Case 2 Low (4.7) = 10.716 (2.28*4.7)
Case 1 LOW + Case 2 HIGH = 10.716
Case 2 LOW (4.7) + Case 2 LOW (4.7) = 22.09 (4.7*4.7)
1 High 2 LoW = 1 LOW 2 HIGH
Now if we change Case 2 to have 6.0 Low range
Then 1HIGH (2.28) 2 LOW(6.0) = 13.68
BUT 1LOW 2 HIGH = 10.716 again
WHILE 1low 2 low = 28.2
So I got some of it right, but not all I guess. For clarification, the 1st 2 are still 4wd even though the first t-case is in 2wd:
2hi 1:1 + 4hi 2.28 = 2.28 (4hi)
2hi 1:1 + 4lo 4.7 = 4.7 (4lo)
4hi 2.28 + 4lo 4.7 = 10.716 (2.28*4.7) (4lo-lo)
4lo 4.7 + 4hi 2.28 = 10.716 (4.7*2.28) (4lo-lo)
4lo 4.7 + 4lo 4.7 = 22.09 (4.7*4.7) (4lo-lo-lo)
So hi + lo or lo + hi cancel each other out and you end up with the same gear reduction because both t-cases are the same. But if you put the 6:1 gears in the 2nd transfer case it changes a little, I sort of got the lo-lo-lo part the first time.
2hi 1:1 + 4hi 2.28 = 2.28 (4hi)
2hi 1:1 + 4lo 6.0 = 6.0 (4lo)
4hi 2.28 + 4lo 6.0 = 13.68 (4lo-lo)
4lo 4.7 + 4hi 2.28 = 10.716 (4lo-lo)
4lo 4.7 + 4lo 6.0 = 28.2 (4lo-lo-lo)
Just for my own clarification is this possible:
4lo 4.7 + 2hi 1:1 = 4.7 (4lo)
Giving yourself another low range putting the 6.0 t-case in 2 hi, or do you even retain the 2 hi properties of 2nd t-case? My own thought would be no its not possible, but it couldn't hurt to ask maybe I am wrong.
Thanks in advance for any answers.